So theįollowing Boolean expressions using the laws and theorems of Boolean algebra.įigure of a voltage regulator, a Zener diode of breakdown voltage 15V is employed.ĭetermine the current through the load resistance, the total current and theĬurrent through the diode. So does not conduct current.ĭiode D 1 is in forward biased, and it is an ideal diode. That diodes D 1 and D 2 are ideal diodes.ĭiode D 2 is in reverse biased. Ĭurrent flowing through 3Ω and 4Ω resistors of the circuit given below. The conditions of the problem suggest that diode D1 is forward biased and diode D2 is reverse. For an emitter – base voltage V EB = 600 mV, calculate the emitter – collector voltage V EC (in volts). BJTs came before MOSFETs so we still call the MOSFET version diode connected, even though the diode mosfet is a quadratic device, not exponential. In the circuit shown in the figure, the BJT has a current gain (β) of 50. A transistor in the diode conguration becomes a two terminal device in the case of the BJT, it is actually a PN junction diode (convince yourself this is the case). = 0.2 V, V BE(sat) = 0.8 V for silicon transistor (ie, standardĥ. A transistor having α =0.99 and V BE = 0.7V, is given in the circuit. Assuming V CEsat = 0.2 V and β = 50, find the minimum base current (I B) required to drive the transistor given in the figure to saturation. The given circuit D 2 & D 3 are in forward bias so theyĬonduct current while D 1 &D 4 are in reverse bias so Find the current flows through the 18Ω resistor. Four silicon diodes and a 10 Ω resistor are connected as shown in figure below. ![]() BJT with given parameters: NDE 1x1018cm3, NAB 1x1016cm3, Dn Dp, WB 100nm, và Lp Ln 1µm. Find the emitter efficiency ge, the base transport factor B and the common emitter current gain b of npn. Find IE, VCE and VBC of BJT in the figures 1 and 2. ![]() So it will block the current and diode D 2 is forward biased, so itĢ. SSED Solved problems For Chapter 7 page 1/6. Calculate the current flowing through the resistance R 1 The given circuit has two ideal diodes connected as shown in figure below.
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